Profesi sebagai desain grafis freelance

NAMA : FENDI HIDAYAT SAPUTRA

KELAS : 12.4A.21

Nim : 12181053

DISKUSI KELOMPOK

Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini:

1.    192.168.10.1/30

2.    172.168.10.1/16

3.    172.168.10./22

4.    10.168.5.1/8

5.    10.168.5.1/17

Jawaban

Nomor 1: 192.168.10.1/30

Netmask = 255.255.255.252

In binary = 11111111. 11111111. 11111111.11111100

Used to calculate = 11111100

Network = 2^n

= 2^6

= 64 Network

Host = 2^h-2

     = 2^2-2

     = 2 Host

Nomor 2 : 172.168.10.1/16

Netmask = 255.255.0.0

In Binary = 11111111.11111111.00000000.00000000

Used to calculate = 00000000.00000000

Network = 2^n

        = 2^0

        = 1 Network

Host    = 2^h-2

= 2^16-2

= 65534 Host

Nomor 3 : 172.168.10./22

Netmask : 255.255.252.0

In Binary : 11111111.11111111.11111100.00000000

Used to calculate = 11111100.00000000

Network = 2^n

        = 2^6

        = 64 Network

Host    = 2^h-2

= 2^10-2

= 1022 Host

Nomor 4 : 10.168.5.1/8

Netmask   : 255.0.0.0 

In Binary : 11111111.00000000.00000000.00000000

Used to calculate = 00000000.00000000.00000000

Network = 2^n

        = 2^0

        = 1 Network

Host    = 2^h-2

= 2^24-2

= 167772614 Host

Nomor 5 : 10.168.5.1/17

Netmask : 255.255.128.0

In Binary : 11111111.11111111.10000000.00000000

Used to calculate = 11111111.10000000.00000000

Network = 2^n

        = 2^9

        = 512 Network

Host    = 2^h-2

= 2^15-2

= 32766 Host



saya menghitung Netmask dan In Binary menggunakan IP Calculator, berikut Link di Bawahny!!!!
http://jodies.de/ipcalc?host=192.168.10.1&mask1=30&mask2=